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=Y^2-16Y+15
We move all terms to the left:
-(Y^2-16Y+15)=0
We get rid of parentheses
-Y^2+16Y-15=0
We add all the numbers together, and all the variables
-1Y^2+16Y-15=0
a = -1; b = 16; c = -15;
Δ = b2-4ac
Δ = 162-4·(-1)·(-15)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-14}{2*-1}=\frac{-30}{-2} =+15 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+14}{2*-1}=\frac{-2}{-2} =1 $
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